Integrand size = 19, antiderivative size = 131 \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=\frac {c \left (3 c d^2+2 a e^2\right ) x}{e^4}-\frac {2 c^2 d x^3}{3 e^3}+\frac {c^2 x^5}{5 e^2}+\frac {\left (c d^2+a e^2\right )^2 x}{2 d e^4 \left (d+e x^2\right )}-\frac {\left (7 c d^2-a e^2\right ) \left (c d^2+a e^2\right ) \arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{2 d^{3/2} e^{9/2}} \]
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Time = 0.12 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {1172, 1824, 211} \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=-\frac {\left (7 c d^2-a e^2\right ) \left (a e^2+c d^2\right ) \arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{2 d^{3/2} e^{9/2}}+\frac {x \left (a e^2+c d^2\right )^2}{2 d e^4 \left (d+e x^2\right )}+\frac {c x \left (2 a e^2+3 c d^2\right )}{e^4}-\frac {2 c^2 d x^3}{3 e^3}+\frac {c^2 x^5}{5 e^2} \]
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Rule 211
Rule 1172
Rule 1824
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c d^2+a e^2\right )^2 x}{2 d e^4 \left (d+e x^2\right )}-\frac {\int \frac {-a^2+\frac {c^2 d^4}{e^4}+\frac {2 a c d^2}{e^2}-\frac {2 c d \left (c d^2+2 a e^2\right ) x^2}{e^3}+\frac {2 c^2 d^2 x^4}{e^2}-\frac {2 c^2 d x^6}{e}}{d+e x^2} \, dx}{2 d} \\ & = \frac {\left (c d^2+a e^2\right )^2 x}{2 d e^4 \left (d+e x^2\right )}-\frac {\int \left (-\frac {2 c d \left (3 c d^2+2 a e^2\right )}{e^4}+\frac {4 c^2 d^2 x^2}{e^3}-\frac {2 c^2 d x^4}{e^2}+\frac {7 c^2 d^4+6 a c d^2 e^2-a^2 e^4}{e^4 \left (d+e x^2\right )}\right ) \, dx}{2 d} \\ & = \frac {c \left (3 c d^2+2 a e^2\right ) x}{e^4}-\frac {2 c^2 d x^3}{3 e^3}+\frac {c^2 x^5}{5 e^2}+\frac {\left (c d^2+a e^2\right )^2 x}{2 d e^4 \left (d+e x^2\right )}-\frac {\left (\left (7 c d^2-a e^2\right ) \left (c d^2+a e^2\right )\right ) \int \frac {1}{d+e x^2} \, dx}{2 d e^4} \\ & = \frac {c \left (3 c d^2+2 a e^2\right ) x}{e^4}-\frac {2 c^2 d x^3}{3 e^3}+\frac {c^2 x^5}{5 e^2}+\frac {\left (c d^2+a e^2\right )^2 x}{2 d e^4 \left (d+e x^2\right )}-\frac {\left (7 c d^2-a e^2\right ) \left (c d^2+a e^2\right ) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{2 d^{3/2} e^{9/2}} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.02 \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=\frac {c \left (3 c d^2+2 a e^2\right ) x}{e^4}-\frac {2 c^2 d x^3}{3 e^3}+\frac {c^2 x^5}{5 e^2}+\frac {\left (c d^2+a e^2\right )^2 x}{2 d e^4 \left (d+e x^2\right )}-\frac {\left (7 c^2 d^4+6 a c d^2 e^2-a^2 e^4\right ) \arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{2 d^{3/2} e^{9/2}} \]
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Time = 0.25 (sec) , antiderivative size = 129, normalized size of antiderivative = 0.98
method | result | size |
default | \(\frac {c \left (\frac {1}{5} c \,x^{5} e^{2}-\frac {2}{3} d c \,x^{3} e +2 a \,e^{2} x +3 c \,d^{2} x \right )}{e^{4}}+\frac {\frac {\left (a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}\right ) x}{2 d \left (e \,x^{2}+d \right )}+\frac {\left (a^{2} e^{4}-6 a c \,d^{2} e^{2}-7 c^{2} d^{4}\right ) \arctan \left (\frac {e x}{\sqrt {e d}}\right )}{2 d \sqrt {e d}}}{e^{4}}\) | \(129\) |
risch | \(\frac {c^{2} x^{5}}{5 e^{2}}-\frac {2 c^{2} d \,x^{3}}{3 e^{3}}+\frac {2 c a x}{e^{2}}+\frac {3 c^{2} d^{2} x}{e^{4}}+\frac {\left (a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}\right ) x}{2 d \,e^{4} \left (e \,x^{2}+d \right )}-\frac {\ln \left (e x +\sqrt {-e d}\right ) a^{2}}{4 \sqrt {-e d}\, d}+\frac {3 d \ln \left (e x +\sqrt {-e d}\right ) a c}{2 e^{2} \sqrt {-e d}}+\frac {7 d^{3} \ln \left (e x +\sqrt {-e d}\right ) c^{2}}{4 e^{4} \sqrt {-e d}}+\frac {\ln \left (-e x +\sqrt {-e d}\right ) a^{2}}{4 \sqrt {-e d}\, d}-\frac {3 d \ln \left (-e x +\sqrt {-e d}\right ) a c}{2 e^{2} \sqrt {-e d}}-\frac {7 d^{3} \ln \left (-e x +\sqrt {-e d}\right ) c^{2}}{4 e^{4} \sqrt {-e d}}\) | \(247\) |
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none
Time = 0.26 (sec) , antiderivative size = 394, normalized size of antiderivative = 3.01 \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=\left [\frac {12 \, c^{2} d^{2} e^{4} x^{7} - 28 \, c^{2} d^{3} e^{3} x^{5} + 20 \, {\left (7 \, c^{2} d^{4} e^{2} + 6 \, a c d^{2} e^{4}\right )} x^{3} + 15 \, {\left (7 \, c^{2} d^{5} + 6 \, a c d^{3} e^{2} - a^{2} d e^{4} + {\left (7 \, c^{2} d^{4} e + 6 \, a c d^{2} e^{3} - a^{2} e^{5}\right )} x^{2}\right )} \sqrt {-d e} \log \left (\frac {e x^{2} - 2 \, \sqrt {-d e} x - d}{e x^{2} + d}\right ) + 30 \, {\left (7 \, c^{2} d^{5} e + 6 \, a c d^{3} e^{3} + a^{2} d e^{5}\right )} x}{60 \, {\left (d^{2} e^{6} x^{2} + d^{3} e^{5}\right )}}, \frac {6 \, c^{2} d^{2} e^{4} x^{7} - 14 \, c^{2} d^{3} e^{3} x^{5} + 10 \, {\left (7 \, c^{2} d^{4} e^{2} + 6 \, a c d^{2} e^{4}\right )} x^{3} - 15 \, {\left (7 \, c^{2} d^{5} + 6 \, a c d^{3} e^{2} - a^{2} d e^{4} + {\left (7 \, c^{2} d^{4} e + 6 \, a c d^{2} e^{3} - a^{2} e^{5}\right )} x^{2}\right )} \sqrt {d e} \arctan \left (\frac {\sqrt {d e} x}{d}\right ) + 15 \, {\left (7 \, c^{2} d^{5} e + 6 \, a c d^{3} e^{3} + a^{2} d e^{5}\right )} x}{30 \, {\left (d^{2} e^{6} x^{2} + d^{3} e^{5}\right )}}\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 314 vs. \(2 (122) = 244\).
Time = 0.41 (sec) , antiderivative size = 314, normalized size of antiderivative = 2.40 \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=- \frac {2 c^{2} d x^{3}}{3 e^{3}} + \frac {c^{2} x^{5}}{5 e^{2}} + x \left (\frac {2 a c}{e^{2}} + \frac {3 c^{2} d^{2}}{e^{4}}\right ) + \frac {x \left (a^{2} e^{4} + 2 a c d^{2} e^{2} + c^{2} d^{4}\right )}{2 d^{2} e^{4} + 2 d e^{5} x^{2}} - \frac {\sqrt {- \frac {1}{d^{3} e^{9}}} \left (a e^{2} - 7 c d^{2}\right ) \left (a e^{2} + c d^{2}\right ) \log {\left (- \frac {d^{2} e^{4} \sqrt {- \frac {1}{d^{3} e^{9}}} \left (a e^{2} - 7 c d^{2}\right ) \left (a e^{2} + c d^{2}\right )}{a^{2} e^{4} - 6 a c d^{2} e^{2} - 7 c^{2} d^{4}} + x \right )}}{4} + \frac {\sqrt {- \frac {1}{d^{3} e^{9}}} \left (a e^{2} - 7 c d^{2}\right ) \left (a e^{2} + c d^{2}\right ) \log {\left (\frac {d^{2} e^{4} \sqrt {- \frac {1}{d^{3} e^{9}}} \left (a e^{2} - 7 c d^{2}\right ) \left (a e^{2} + c d^{2}\right )}{a^{2} e^{4} - 6 a c d^{2} e^{2} - 7 c^{2} d^{4}} + x \right )}}{4} \]
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Exception generated. \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.27 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.10 \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=-\frac {{\left (7 \, c^{2} d^{4} + 6 \, a c d^{2} e^{2} - a^{2} e^{4}\right )} \arctan \left (\frac {e x}{\sqrt {d e}}\right )}{2 \, \sqrt {d e} d e^{4}} + \frac {c^{2} d^{4} x + 2 \, a c d^{2} e^{2} x + a^{2} e^{4} x}{2 \, {\left (e x^{2} + d\right )} d e^{4}} + \frac {3 \, c^{2} e^{8} x^{5} - 10 \, c^{2} d e^{7} x^{3} + 45 \, c^{2} d^{2} e^{6} x + 30 \, a c e^{8} x}{15 \, e^{10}} \]
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Time = 13.59 (sec) , antiderivative size = 183, normalized size of antiderivative = 1.40 \[ \int \frac {\left (a+c x^4\right )^2}{\left (d+e x^2\right )^2} \, dx=x\,\left (\frac {3\,c^2\,d^2}{e^4}+\frac {2\,a\,c}{e^2}\right )+\frac {c^2\,x^5}{5\,e^2}-\frac {2\,c^2\,d\,x^3}{3\,e^3}+\frac {x\,\left (a^2\,e^4+2\,a\,c\,d^2\,e^2+c^2\,d^4\right )}{2\,d\,\left (e^5\,x^2+d\,e^4\right )}-\frac {\mathrm {atan}\left (\frac {\sqrt {e}\,x\,\left (c\,d^2+a\,e^2\right )\,\left (a\,e^2-7\,c\,d^2\right )}{\sqrt {d}\,\left (-a^2\,e^4+6\,a\,c\,d^2\,e^2+7\,c^2\,d^4\right )}\right )\,\left (c\,d^2+a\,e^2\right )\,\left (a\,e^2-7\,c\,d^2\right )}{2\,d^{3/2}\,e^{9/2}} \]
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